How many ml of 0.213-M Na3PO4 are required to deliver 66.4 mmol Na1+ ions?

Given :

Molarity of , M = 0.213 M .

To Find :

How many ml of 0.213 M of are required to deliver 66.4 mmol .

Solution :

Volume required  :

So ,

Therefore , volume of required is 103.91 ml .

Hence , this is the required solution .

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