A 1.00-mole sample of C6H12O6 was placed in a vat with 100 g of yeast. If 32.3 grams of C2H5OH was obtained, what was the percent yield of C2H5OH?

y = 35.06 %.

Explanation:

The reaction of fermentation is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂      (1)        

From the reaction (1) we have that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH, then the number of moles of C₂H₅OH is:

Now, we need to find the mass of C₂H₅OH:

Finally, the percent yield of C₂H₅OH is:

Therefore, the percent yield of C₂H₅OH is 35.06 %.

I hope it helps you!

d : a person who learns about the world by observing it. no that is not a smiley face

explanation: