Water is being pumped out of a reservoir at a rate of 2.54 liters per 15.0 seconds. If the reservoir contains 1.0500 x 106 gallons of water, how many hours will it take to empty it?

It will take 6,519.44 hours to empty the reservoir.

Explanation:

First of all, you should know that 1 gallon = 3.785 L

So, you can apply the following rule of three to know the amount of water in liters in the reservoir: if 1 gallon is 3.785 liters, 1.0500 * 10⁶ gallons of water, how many liters are they?

amount= 3,974,250 liters

Knowing that water is pumped out of a reservoir at a rate of 2.54 liters every 15.0 seconds, you now want to pump 3,974,250 liters of water out of the reservoir. For that you apply the following rule of three: if 2.54 liters are pumped out every 15 seconds, how long does 3,974,250 liters take to be pumped out?

time= 23,469,980.32 seconds

With 1 hour 60 minutes and 1 minute equal to 60 seconds, then 1 hour represents 3,600 seconds. So you apply the following rule of three: if 3,600 seconds is 1 hour, 23,469,980.32 seconds, how many hours are they?

time=6,519.44 hours

It will take 6,519.44 hours to empty the reservoir.

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