Draw structures for compounds that meet the following descriptions in proton NMR:a) C2H6O; one singletb) C3H7Cl; one doublet and one septetc) C4H8Cl2O; two tripletsd) C4H8O2; one singlet, one triplet, and one quartet

The structures are shown in the attachments.

Explanation:

Please see the attachments below for the structures.

Explanation:

There is only one environment denoted as 'a'.

Using the (n+1) rule to determine the multiplicity, m

where is the number of neighboring Hydrogen, then

Since, n = 0, then

m = 0 + 1 = 1 (which means singlet)

Hence, one singlet

There are two environments denoted as 'a' and 'b'

For 'a' ; n = 6

Hence, m = n + 1

m = 6 + 1  = 7 (this means septet)

For 'b'; n = 1

then, m = n + 1

m = 1 + 1  = 2 (this means doublet)

Hence, one septet, one doublet

There are two environments denoted as 'a' and 'b'

For 'a' ; n = 2

then, m = n + 1

m = 2 + 1  = 3 (this means triplet)

For 'b' ; n = 2

then, m = n + 1

m = 2 + 1  = 3 (this means triplet)

Hence, two triplets

There are three environments denoted as 'a', 'b', and 'c'

For 'a' ; n = 0

Hence, m = n + 1

m = 0 + 1  = 1 (this means singlet)

For 'b' ; n = 3

then, m = n + 1

m = 3 + 1  = 4 (this means quartet)

For 'c' ; n = 2

then, m = n + 1

m = 2 + 1  = 3 (this means triplet)

Hence, one singlet, one triplet, and one quartet

c (diamond),

sio2 (quartz)

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