5. The density of a substance is 3.4 x 10^3 g/mL. Mixing it with another substance increases the density by 1.5 X 10^1 times. What is the density of the mixture? 6. A compound contains atoms of sulfur and iron. There are 3.6 X 10^20 atoms of iron in the compound. Divide the nu of iron atoms by 1.8 X 10^- 4 to find the number of sulfur atoms in the compound?

5.   the total density of the mixture = 3.415 x 10^3 g/mL

6.  the number of sulfur atoms in the compound =  2 x 10^24

Explanation:

5.

given:

density of a substance is 3.4 x 10^3 g/mL

Mixing it with another substance increases the density by 1.5 x 10^1 times.

find:

What is the density of the mixture?

let density (a) = 3.4 x 10^3 g/mL

density(b) = 1.5 x 10^1 g/mL

since there is no specific density provided for the mixture, we then add both to increase the density,

total density = density(a) + density(b)

total density = 3.4 x 10^3 g/mL + 1.5 x 10^1 g/mL

total density = 3.415 x 10^3 g/mL

therefore,

the total density of the mixture = 3.415 x 10^3 g/mL

6.

given:

A compound contains atoms of sulfur and iron.

There are 3.6 X 10^20 atoms of iron in the compound.

find:

Divide the no of iron atoms by 1.8 X 10^- 4 to find the number of sulfur atoms in the compound?

iron = 3.6 x 10^20  ⇒ to divide 1.8 X 10^- 4

sulfur atoms = 3.6 x 10^20    =  2 x 10^24

                         1.8 X 10^- 4

therefore,

the number of sulfur atoms in the compound =  2 x 10^24

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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