The molar mass of CsF is 151.9 g/mol. How many grams of CsF are needed to prepare 300.0 mL of 0.0500 M CsF solution?

2.28 g of CsF.

Explanation:

The following data were obtained from the question:

Molar mass of CsF = 151.9 g/mol.

Volume = 300 mL

Molarity of CsF = 0.05 M

Mass of CsF =.?

Next, we shall convert 300 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

300 mL = 300 mL /1000 mL × 1 L

300 mL = 0.3 L

Therefore, 300 mL is equivalent to 0.3 L

Next, we shall determine the number of mole CsF in the solution. This can be obtained as follow:

Volume = 0.3 L

Molarity of CsF = 0.05 M

Mole of CsF =.?

Molarity = mole /Volume

0.05 = mole of CsF /0.3

Cross multiply

Mole of CsF = 0.05 × 0.3

Mole of CsF = 0.015 mole.

Finally, we shall determine the mass of CsF needed to prepare the solution as follow:

Mole of CsF = 0.015 mole.

Molar mass of CsF = 151.9 g/mol.

Mass of CsF =.?

Mole = mass /Molar mass

0.015 = mass of CsF /151.9

Cross multiply

Mass of CsF = 0.015 × 151.9

Mass of CsF = 2.28 g

Therefore, 2.28 g of CsF is needed to prepare the solution.

14,16 18 reacts with group

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.