If you find the mass of a sample to be 42.1 g and the actual mass is 42.0 g. What wold be the percent error

0.24%

Explanation:

The following data were obtained from the question:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error can be obtained by using the following formula:

Percentage error = |Measured value – Actual value | / Actual value × 100

With the above formula, we can obtain the percentage error as follow:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error = |42.1 – 42| / 42 × 100

Percentage error = 0.1/42 × 100

Percentage error = 10/42

Percentage error = 0.24%

Therefore, the percentage error is 0.24%

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer