Calculate the millimoles of solute in 1.88 L of a 0.00713 M NaCN solution. millimoles:

13.4 milimoles.

Explanation:

The following data were obtained from the question:

Volume = 1.88 L

Molarity = 0.00713 M

Millimoles of NaCN =?

Next, we shall determine the number of mole NaCN in the solution. This can be obtained as follow:

Molarity = mole /Volume

Volume = 1.88 L

Molarity = 0.00713 M

Mole of NaCN =?

Molarity = mole /Volume

0.00713 = moles of NaCN /1.88

Cross multiply

Mole of NaCN = 0.00713 × 1.88

Mole of NaCN = 0.0134 mole

Finally, we shall convert 0.0134 mole to Millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

0.0134 mole = 0.0134 × 1000

0.0134 mole = 13.4 milimoles

Therefore, the millimoles of the solute, NaCN in the solution is 13.4 milimoles

the ratio of the conjugate base to the acid required to attain the desired ph.