A sample of xenon gas collected at a pressure of 948 mm Hg and a temperature of 283 K has a mass of 128 grams. What is the volume of the sample in Liters?

V = 1.84 × 10³ L

Explanation:

You need to use the Ideal Gas Law and solve for volume.

PV = nRT

V = nRT/P

First, you need to convert the pressure to atm.

1 atm = 760 mm Hg

948/760 = 1.247 atm

Next, convert grams of xenon to moles.  The molar mass is 131.293 g/mol.

128/131.293 = 0.975 mol

You now have all of the values needed.

P = 1.247 atm

n = 0.975 mol

R = 8.314 J/mol*K

T = 283 K

Plug the values in and solve.

V = nRT/P

V = (0.975 × 8.314 × 283)/1.247

V = 1.84 × 10³ L

The volume of the sample will be 1.84 × 10³ L.

un recipient conține 6,4 moli de gaz. gazul hidrogen reprezintă 25% din totalul kilometrilor din container. în cazul în care presiunea totală este de 1.24 atm ceea ce este