How many moles of NaOH are present in 65.00 g of NaOH(s)? *

Explanation:

To find the number of moles we must first find the molar mass of the compound after that we use the formula

where

n is the number of moles

M is the molar mass

m is the mass

M(Na) = 23 , M(O) = 16 , M(H) = 1

Molar mass ( NaOH ) = 23+ 16 + 1

= 40 g/mol

mass = 65 g

Substitute the values into the above formula and solve

That's

We have the final answer as

Hope this helps you

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles