The density of lead, which has the FCC structure, is 11.36 . The atomic weight of lead is 207.19 . Use Avogadro's number: 6.02210. Calculatethe lattice parameter(Enter your answer to three significant figures.) = 2.75*10^21 the atomic radius of lead(Enter your answer to three significant figures.) =
Answers: 1
![a_o = \sqrt[3]{V }](/tpl/images/0748/9324/a210e.png)
![a_o = \sqrt[3]{1.211 5 *10^{-22} }](/tpl/images/0748/9324/32761.png)
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The density of lead, which has the FCC structure, is 11.36 . The atomic weight of lead is 207.19 . U...
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