What is the final chemical equation from the following intermediate chemical equations? 2 equations. First: upper P subscript 4 upper O subscript 6 (s) right arrow upper P subscript 4 (s) plus 3 upper O subscript 2 (g). Second: upper P subscript 4 (s) plus 5 upper O subscript 2 (g) right arrow upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) plus 2 upper O subscript 2 (g) right arrow upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) plus 8 upper O subscript 2 (g) right arrow 2 upper P subscript 4 (s) plus upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) plus 15 upper O subscript 2 (g) right arrow upper P subscript 4 (s) plus upper P subscript 4 upper O subscript 10 (s). Upper P subscript 4 upper O subscript 6 (s) StartFraction 5 over 3 EndFraction upper O subscript 2 (g) right arrow upper P subscript 4 upper O subscript 10 (s).

Happy new years every one

Is there an image with it

Because you ate playdough

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.