a beaker contains 0.250 l of liquid. a student pours 0.00385 L of liquid out of the beaker. How much liquid remains in the beaker? choose the value reported with the correct number of significant figures

The volume of the liquid remaining in the beaker is 0.24615 l

Explanation:

The initial volume of liquid in the beaker = 0.250 l

The volume of liquid the student pours out of the beaker = 0.00385 l

The volume of liquid remaining in the beaker, V, is given as follows;

V = The initial volume of liquid in the beaker - The volume of liquid the student pours out of the beaker

Therefore, we have;

V = 0.250 l - 0.00385 l = 0.24615 l

The volume of the liquid remaining in the beaker is 0.24615 l.

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vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.