People buying food in sealed bags at high elevations often notice that the bags are puffed up because the air inside has expanded. A bag of pretzels was packed at a pressure of 1.01 atm and a temperature of 21.0°C. When opened at a summer picnic in Santa Fe, New Mexico, at a temperature of 31.0°C, the volume of the air in the bag is 1.40 times its original volume. What is the pressure of the air (in atm)?

The pressure in Santa Fe, New Mexico is 0.746atm

Explanation:

You can solve this question using combined gas law:

P₁V₁ / T₁ = P₂V₂ / T₂

Where P is pressure,

V is volume,

and T is absolute temperature in K for 1, initial state and, final states.

The initial conditions are:

P₁ = 1.01atm

V₁ = 1

T₁ = 21.0°C + 273.15K = 294.15K

And final conditions are:

P₂ = Our unknown

V₂ = 1.4

T₂ = 31.0°C + 273.15K = 304.15K

Replacing:

P₁V₁ / T₁ = P₂V₂ / T₂

1.01atm*1 / 294.15K = P₂*1.4 / 304.15K

P₂ = 0.746atm

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

i think the answer is terrae but not 100 percent sure. ▓▬▬ §