A certain sample of a gas has a volume of 20 L at 0 oC and 1 atm. A plot of the experimental data of its volume against the Celsius temperature, θ, at constant P, gives a straight line of slope 0.0741 L(C)^-1. From these data alone (without making use of the perfect gas law), determine the absolute zero of temperature in degrees Celsius.

The absolute zero temperature T = - 269.91° C

Explanation:

From the given information:

The plot of the volume of the experimental data against the celsius temperature can be expressed mathematically as:

V = mT + c

V = 0.0741 × T+c --- (1)

where;

m, which is the straight line of the slope = 0.0741

replacing the value of V to be = 20 L, T= 0.

Then:

20 = 0.0741 × 0 + c

20 = c

From equation (1), replacing the value of c with 20, we have:

V = 0.0741 × T+20

SO, to determine absolute zero temperature: we have the volume to be zero at absolute zero temperature, Thus:

0 = 0.0741 × T+20

0.0741 T + 20  = 0

0.0741 T = - 20

T = - 269.91° C

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer