19mg of 9-fluorenone is dissolved in 5ml of diethyl ether. The resulting organic solution is extracted with 10ml of water. The Kp for 9-fluorenone in diethyle ether/water is 9.5, how much would remian in the ether layer?

The value is

Explanation:

From the question we are told that

The mass of 9-fluorenone is m = 19 mg

The volume of diethyl ether V = 5 ml

The volume of water is

The equilibrium constant for 9-fluorenone is

Generally the equilibrium constant for 9-fluorenone is mathematically represented as

Here z is the remaining mass of 9-fluorenone

=>

=>

=>

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"