At 0.00 °C and 1.00 atm pressure, a sample of gas occupies 20.0 ml. If the temperature is increased to 30.0°C and the entire gas sample is transferred to a 30.0-ml container. The pressure of the gas in the new container is:
0.499 atm
0.740 atm
1.35 atm
O 1.66 atm

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

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hope it ,

bioteacher101