Amixture is made by combining 1.64 lb of salt and 4.66 lb of water. what is the percentage of salt (by mass) in this mixture?

Answer : The percentage of salt in the mixture is 73.65 %

Explanation : Given,

Mass of salt = 1.64 lb

Mass of water = 4.66 lb

First we have to calculate the mass of mixture.

Mass of mixture = Mass of salt + Mass of water

Mass of mixture = 1.64 + 4.66 = 6.3 lb

Now we have to calculate the percentage of salt in the mixture.

Formula used :

Now put all the given vales in this formula, we get:

Therefore, the percentage of salt in the mixture is 73.65 %

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole