Show a numerical setup for calculating the quantity of heat in joules required to completely vaporize 102.3 grams of H2O(l) at 100°C and 1.0 atm.

The heat required to vaporize 102.3 grams of H₂O(l) is 231198 J.

Explanation:

The heat required to vaporize 102.3 g of H₂O(l) can be calculated as follows:

Where:

q: is the heat  

ΔHv: is the heat of vaporization of water = 2260 J/g

m: is the mass = 102.3

Therefore, the heat required to vaporize 102.3 grams of H₂O(l) is 231198 J.

I hope it helps you!

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.