2. A lab group turned in their experiment and had measured the mass of their sample to be 3.15 g. The teacher had asked for them to make a sample of 3.10 g (the
accurate value). What is their percent error?

1.61%.

Explanation:

The following data were obtained from the question:

Measured mass = 3.15 g.

Actual mass = 3.10 g

Percentage error =.?

The percentage error of the group can be obtained by using the following equation below:

Percentage error = |Actual mass – Measured mass| / Actual mass × 100

Percentage error = |3.10 – 3.15| /3.10 × 100

Percentage error = 0.05/3.1 × 100

Percentage error = 5/3.1

Percentage error = 1.61%

Therefore, the percentage error of the group is 1.61%.

it should be all of them because it asks if you included all of those in your answer

explanation:

1. they vary with a higher number because boiling is way hotter than melting