The energy needed for the following process is 1.960 × 104 kJ/mol: Li(g) → Li3+(g) + 3e− If the first ionization energy of lithium is 5.20 × 102 kJ/mol, calculate the second ionization energy of lithium—that is, the energy required for the process: Li+(g) → Li2+(g) + e− A hydrogen-like ion is an ion containing only one electron. The energies of the electron in a hydrogen-like ion are given by En = −(2.18 × 10−18 J) (Z2)(1/n2) where En is the energy of the electron in the hydrogen-like ion, n is the principal quantum number, and Z is the atomic number of the element. Second ionization energy of lithium: × 10 kJ/mol (Enter your answer in scientific notation)
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Chemistry, 21.06.2019 15:20
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The energy needed for the following process is 1.960 × 104 kJ/mol: Li(g) → Li3+(g) + 3e− If the firs...
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