6. Mr. K is trsins so identify a white crystal he found this summer by determining the density of it. He placed it on a scale and it massed out at 51.00 grams. When he placed it in 50.0 mL of water, the level
rose to 61.4 mi. Can you identify the mineral based on density.
Nlineral Barite Calcite Gypsum
Density (cm) 4.48
2.71
2.36

Option A is correct (barite)

Explanation:

Given data:

Mass of  mineral = 51.00g

Volume of water = 50.0 mL

Volume of water + mineral = 61.4 mL

Density of mineral = ?

Solution:

First of all we will calculate the volume of mineral.

Volume of mineral = (volume of water + mineral) - Volume of water

Volume of mineral = 61.4 mL - 50.0 mL

Volume of mineral = 11.4 mL

Density of mineral:

d = m/v

d = 51.00 g / 11.4 mL

d = 4.48 g/cm³ (1mL = 1 cm³ )

Thus the mineral is barite.