Isoamyl salicylate ( = 208.25 g/mol) has a pleasant aroma and is used in perfumes and soaps. which of the following combinations gives a 0.75 m solution of isoamyl salicylate in ethyl alcohol (d = 0.7893 g/ml)?
a. 117.2 g isoamyl salicylate in 950.0 ml of ethyl alcohol
b. 117.2 g isoamyl salicylate in 750.0 ml of ethyl alcohol
c. 117.2 g isoamyl salicylate in 750.0 ml of solution
d. 117.2 g isoamyl salicylate in 592.0 g of ethyl alcohol

The correct answer is Option C.

Explanation:

We are given:

Molarity of isoamyl salicylate = 0.75 M

This means that 0.75 moles of isoamyl salicylate is present in 1 L or 1000 mL of solution.

Moles of isoamyl salicylate = 0.75 moles

Molar mass of isoamyl salicylate = 208.25 g/mol

Putting values in above equation, we get:

By applying unitary method, we get:

156.19 grams of isoamyl salicylate is present in 1000 mL of solution.

So, 117.2 grams of isoamyl salicylate will be present in = of solution.

Thus, 117.2 grams of isoamyl salicylate is present in 750 mL of solution.

Density of solution = 0.7893 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

By applying unitary method, we get:

156.19 grams of isoamyl salicylate is present in 789.3 g of solution.

So, 117.2 grams of isoamyl salicylate will be present in = of solution.

Thus, 117.2 grams of isoamyl salicylate is present in 592 g of solution.

Hence, the correct answer is Option C.