Which of the following conversion factors is correct to convert 0.25 moles of Na to particles of Na?

6.02×10²³ particles / 1 mol

Explanation:

In this question the choices are missed.

For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.

1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final

0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles

In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

the answer is symmetrical : )