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The specific heat capacity of chromium is 0.449 j/g.°C thus given metal is chromium.

Explanation:

Given data:

Mass of metal = 24 g

Initial temperature = 20 °C

Final temperature = 45°C

Energy absorbed by metal = 269.4 j

Which metal is this  = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 45°C - 20 °C

ΔT = 25°C

269.4 j = 24 g × c × 25°C

269.4 j = 600 g.°C× c

c = 269.4 j/600 g.°C

c =0.449 j/g.°C

The specific heat capacity of chromium is 0.449 j/g.°C thus given metal is chromium.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.