For an equimolar solution of n-pentane and n-hexane, compute: a) The dew-point pressure at 1450F b) The bubble-point temperature at 2.3 bar c) The vapor fraction, at 145.F and 0.75 atm, and the mole fractions of the vapor and liquid phases d) Report the critical temperature, pressure and find the MSDS of both chemicals

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It decreases by 4 is your answer mark brainliest 

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -