A 5.0-L sample of sulfur hexafluoride (SF6) is stored at a temperature of 250.0 K and a pressure of 67.0 Pa. If the pressure is decreased to 60.0 Pa, what will the new temperature be?

279.1 K

Explanation:

You'll be using Gay-Lussac's Law for this. P1/T1=P2/T2

I have a class for this, and one of the practice questions was formatted this way, so I used that format and substituted said numbers as needed

P1:67 Pa

P2:60 Pa

T1:250 K

T2:?

I really hope this helps!

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2