Analyze the example of this door knob wheel and axle. • The radius of the wheel, or in this case the handle, is 4.125 inches.
• The radius of the axle that opens the latch (inside the mechanism) is 0.125 inch. The actual effort force needed to open the door is 2.25 pounds.
The efficiency of this type of door knob is 85%.
Calculate the ideal mechanical advantage of this wheel and axle system when the resistance force is applied to the axle.
Formula, substitute, final answer

28

Explanation:

Velocity ratio= Radius of wheel/radius of axle

Radius of wheel= 4.125 inches

Radius of axle= 0.125 inches

Velocity ratio = 4.125/0.125 = 33

Then;

Efficiency = mechanical advantage/velocity ratio × 100

Since the efficiency of the system = 85%

85 = mechanical advantage/33 × 100

Mechanical advantage = 85 × 33/100 = 28

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.

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