The bowling ball weighs 3.6 kg and the bowling pin weighs 1.36 kg. If the mass of the bowling ball is increased to 7.2 kg and the bowling pin is increased to 2.7 kg, what is the effect on the force between them? Group of answer choices

F₂ = 3.97 F₁

Hence, the force will be increased by a factor of 3.97

Explanation:

The force between the ball and the bowling pin is given by Newton's Gravitational Law, as follows:

F = Gm₁m₂/r²

where,

F = Force

G = Gravitational Constant

m₁ = mass of ball

m₂ = mass of bowling pin

r = distance between ball and bowling pin

So, initially:

F₁ = G(3.6 kg)(1.36 kg)/r²

F₁ = 4.896 G/r²

After increase in masses:

F₂ = G(7.2 kg)(2.7 kg)/r²

F₂ = 19.44 G/r²

F₂/F₁ = (19.44 Gr²)/(4.896 G/r²)

F₂ = 3.97 F₁

Hence, the force will be increased by a factor of 3.97