Using the equations, answer the following question. Reaction A: N2 + O2 + energy --> 2NO
Reaction B: CH4 + 2O2 --> CO2 + 2H2O + energy
Reaction C: H2 + F2 --> 2HF + energy
Reaction D: 6CO2 + 6H2O + energy --> C6H12O6 + 6O2

Which reaction(s) would you expect to release light or heat?

Using dilution equationm1v1 =m2v2 ; where m1 and m1 are the intiial and final concentration, and v1 and v2 are the initial and final volume.5  × 5 m = 8 l  × m2m2 = 25/8 = 3.125 mtherefore; the resulting molarity is 3.125 m

The answer is 5 10 15

Electron equations of the given changes are as follow,a)                              cu      →      cu⁺²  + 2e⁻b)                              mg⁺²  +  2 e⁻      →      mgc)                              cl⁻    →      cl  +  1e⁻d)                              s  +  2 e⁻    →      s²⁻e)                                o²⁻      →      o  +  2 e⁻f)                              p  +  3 e⁻    →      p³⁻g)                              fe²⁺    →      fe³⁺  + 1 e⁻h)                              s²⁻    →      s⁴⁺  +  6 e⁻