Chemistry, 15.10.2020 17:01 ghwolf4p0m7x0

Which element has an outer(ending) electron configuration of s2p4?

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Answer from: GabbyLandry

An element which has an outer (ending) electron configuration of s^2p^4 is: Oxygen.

Electron configuration can be defined as a formula that is used to denote the distribution of the atoms of a chemical element in an atomic orbital.

Basically, electron configuration uses four (4) main letters to illustrate the distribution of atoms in an atomic orbital:

spdf

The electron configuration of s^2p^4 indicates that the chemical element is in Group 6 and has six (6) electrons in its outermost shell.

Hence, a chemical element such as Oxygen (O) or Selenium (Sn) in Group 6 of the periodic table would have an electron configuration of s^2p^4 .

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Answer from: amanda2003teddy

The question is in complete, the complete question is:

Which element has an outer electron configuration of s 2 p4 ?

(A) Ca (B) Cr (C) Ge (D) Se

(D) Se

Explanation:

The outer electronic configuration of an atom reflects the group to which it belongs in the periodic table. Each group has its unique outermost electron configuration and number of electrons found in the outermost shell of the atoms of elements in the group.

s 2 p4 is the unique outermost electron configuration of group 16 elements. Group 16 elements have six electrons in their outermost shell. If we consider the options, only Se is a member of group 16. Hence it is only Se that has the outermost electron configuration s 2 p4 .

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Answer from: Quest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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