Chemistry, 24.08.2019 03:30 oscaryn7213

Complete and balance the molecular equation, including phases, for the reaction of aqueous sodium sulfate, na2so4, and aqueous barium nitrate, ba(no3)2.

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The complete chemical reaction of aqueous Sodium sulfate and aqueous Barium nitrate is

$Na_{2} SO_{4} (aq) + Ba(NO_3)_2(aq) -\ \textgreater \ BaSO_4(s) + 2NaNO_3(aq)$

The right side and the left side of the reaction have equal number of elements, therefore it is balanced.

Answer from: joannakawata6

The complete and balanced molecular equation is as follows:

$\boxed{{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Ba}}{{\left({{\text{N}}{{\text{O}}_{\text{3}}}}\right)}_2}\left({aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left( {aq}\right)+2{\text{NaN}}{{\text{O}}_3}\left({aq}\right)}$

Further Explanation:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Double displacement reaction is defined as the reaction in which ions of two compound interchange with each other to form the product. For example, the general double displacement reaction between two compound AX and BY is as follows:

${\text{AX}}+{\text{BY}}\to{\text{AY}}+{\text{BX}}$

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the double displacement reaction, sodium sulfate $\left({{\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}}\right)$ reacts with barium nitrate $\left({{\text{Ba}}{{\left({{\text{N}}{{\text{O}}_3}}\right)}_2}}\right)$ to form ${\text{BaS}}{{\text{O}}_4}$ and ${\text{NaN}}{{\text{O}}_3}$ . The physical state of ${\text{NaN}}{{\text{O}}_3}$ , ${\text{Ba}}{\left({{\text{N}}{{\text{O}}_{\text{3}}}}\right)_2}$ , ${\text{BaS}}{{\text{O}}_4}$ and ${\text{NaN}}{{\text{O}}_3}$ is aqueous. The unbalanced chemical equation is as follows:

${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left( {aq}\right)+{\text{Ba}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}}\right)_2}\left( {aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left({aq}\right)+{\text{NaN}}{{\text{O}}_3}\left( {aq}\right)$

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

•On reactant side,

Number of sodium atoms is 2.

Number of sulfur atom is 1.

Number of oxygen atoms is 10.

Number of barium atom is 1.

Number of nitrogen atoms is 2.

•On product side,

Number of sodium atom is 1.

Number of sulfur atom is 1.

Number of oxygen atoms is 7.

Number of barium atom is 1.

Number of nitrogen atoms is 1.

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. Barium and sulfur atoms are balanced on both sides. To balance the number of sodium and nitrogen atom multiply ${\text{NaN}}{{\text{O}}_{\text{3}}}$ by 2. Now the reaction is,

${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Ba}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}}\right)_2}\left({aq}\right) \to{\text{BaS}}{{\text{O}}_4}\left({aq}\right)+\boxed2{\text{NaN}}{{\text{O}}_3}\left({aq}\right)$

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. The number of oxygen, hydrogen, and carbon atoms are same on both sides. Now the reaction is,

${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Ba}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}}\right)_2}\left({aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left({aq}\right)+2{\text{NaN}}{{\text{O}}_3}\left({aq}\right)$

Step 5: Finally, we check the number of atoms of each element on both the sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:

${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_4}\left({aq}\right)+{\text{Ba}}{\left( {{\text{N}}{{\text{O}}_{\text{3}}}}\right)_2}\left({aq}\right)\to{\text{BaS}}{{\text{O}}_4}\left({aq}\right)+2{\text{NaN}}{{\text{O}}_3}\left({aq}\right)$

Learn more:

1. Balanced chemical equation:

2. Number of covalent bonds does nitrogen formed with its unpaired:

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, Na2SO4, Ba(NO3)2, BaSO4, NaNo3, physical state, aqueous, coefficients, and double displacement reactions.

Answer from: Quest

Herbivores, carnivores, omnivores, decomposers, herbivores

Answer from: Quest

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.

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