Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product of the instantaneous amounts of A and B not converted to chemical C. Initially, there are 100 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 10 grams of C is formed in 7 minutes. How much is formed in 28 minutes? (Round your answer to one decimal place.) grams What is the limiting amount of C after a long time? grams How much of chemicals A and B remains after a long time? A grams B grams At what time is chemical C half-formed? t = min

Follows are the solution:

Explanation:

A + B = C

Its response decreases over time as well as consumption of a reactants.  

r = -kAB

during response A convert into 2x while B convert into x to form 3x of C

let's  y = C

y = 3x

Still not converted sum of reaction  

for A: 100 - 2x

for B: 50 - x

Shift of x over time  

Integration of x as regards t  

D is the constant of integration

initial conditions: t = 0, x = 0

hence we get:

after t = 7 minutes ,

Insert the above value x into equation to get k.  

therefore plugging in the equation the above value of k  

Let y = C

, calculate C:

y = 3x

amount of C formed in 28 mins

plug t = 28

therefore amount of C formed in 28 minutes is = 3x = 144.78 grams

C:

y= 136.5 =137

a is the answer to this question

explanation:

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.