1. Determine the electron-domain geometry and molecular geometry for each of the following. a. SBr2b. PI4+c. IBr2−2. The following three compounds all have the same general formula, XF4. Compare the electron-domain geometries of these three compounds and explain what characteristic(s) of the central atom causes differences in geometry. a. SiF4:b. SeF4:c. XeF4:

SBr2

Electron geometry-tetrahedral; molecular geometry-trigonal pyramidal

PI4+

Electron geometry-tetrahedral; moleculargeometry-tetrahedralr

IBr2

Electron geometry - tetrahedral ; molecular shape - bent

Explanation:

We have to carefully consider the issues in question 2.

First of all, the compound SiF4 is an AX4 molecule so both it's electron domain geometry and molecular geometry are tetrahedral. The molecule has no lone pairs.

For SeF4, the compound is a molecule of the type AX4E, its molecular geometry is trigonal bipyramid but its molecular geometry is see-saw because of the presence of a lone pair of electrons on the central atom, selenium.

For XeF4, the electron domain geometry is octahedral but its molecular geometry is square planar. The molecule is of the type AX4E2 and the two lone pairs are positioned above and below the plane of the square.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).