the density of an 18.0 solution of ammonium sulfate is 1.10g/ml. What mass of Ammonium sulfate is required to prepare 275ml of this solution

Therefore, 54.45 g of Ammonium sulphate is required

Explanation:

Molar mass of ammonium sulphate, (NH₄)₂SO₄ = 132 g/mol

Since density of solution is 1.10 g/ml, a 1 mL solution has mass = 1.10 g

275 mL solution will have a mass = 275 * 1.10 = 302.5 g

Since the solution is 18% ammonium sulphate by weight,

mass of ammonium sulphate present in 275 mL solution = 302.5 * 18/100

mass of ammonium sulphate present in 275 mL solution = 54.45 g

Therefore, 54.45 g of Ammonium sulphate is required

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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