А. B
Which of the following is true about the picture above? What would it be?

Container A is a solution and Container B is a colloid.

Explanation:

Container A is a solution as the tyndall efffect is not present. You cannot see the light bean through the glass.

Container B is a suspension or a colloid as you can see the beam through the glass.

The first option proposes Container A is a colloid...this is not correct

The third option is not true as the tyndall effect is only displayed in container B

The fourth option is not correct the tyndall effect is not present in container A meaning it would not be a suspension or a colloid and you can see the tyndall effect in container B indicating its not a solution

the answer is na (sodium)

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2