1. An oxide of chromium is found to have the following % composition: 68.4% Cr and 31.6% 0. Determine this compound's empirical formula.

Empirical formula is Cr₂O₃.

Explanation:

Given data:

Percentage of Cr = 68.4%

Percentage of O = 31.6%

Empirical formula = ?

Solution:

Number of gram atoms of Cr = 68.4 / 52 = 1.3 2

Number of gram atoms of O = 31.6 / 16 = 1.98

Atomic ratio:

                            Cr               :         O

                           1.32/1.32     :       1.98/1.32

                               1              :        1.5

Cr : O = 1 :  1.5

Cr : O = 2(1 : 1.5)

Empirical formula is Cr₂O₃.

you need to have a picture of the atom that way we can answer it

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.