I tooktwo plants that like 3% NaCl environments and I put one in a 3M NaCl solution and a 0.6M NaCl solution. Describe what will happen to each plant. Hint: convert the molarity into percentag

In the 3M NaCl solution, is plant will wilt and die due to loss of water from its cell as the solution is far too hypertonic.

In the 0.6M NaCl solution, this plant will thrive as the solution is a fairly 3% NaCl environment.

Explanation:

Molar mass of of NaCl = 58.5 g/mol, Density of water = 1 g/mL; 1 Litre = 1000  mL

3M or 3 mol/dm³ NaCl solution contains 3 moles of NaCl in 1 litre of solution.

3 moles of NaCl has a mass of 3 * 58.5 g = 175.5 g

Percentage solution = (175.7 g / 1000 g ) * 100 = 17.55% NaCl

0.6M or 0.6 mol/dm³ NaCl solution contains 0.6 moles of NaCl in 1 litre of solution.

0.6 moles of NaCl has a mass of 0.6 * 58.5 g = 35.1 g

Percentage solution = (35.1 g / 1000 g ) * 100 = 3.51% NaCl

In the 3M NaCl solution, is plant will wilt and die due to loss of water from its cell as the solution is far too hypertonic.

In the 0.6M NaCl solution, this plant will thrive as the solution is a fairly 3% NaCl environment.

law of conservation of matter