Consider the reaction: CH3COOH(aq)+H2O(l)⇌H3O+(aq)+CH3COO− (aq) K=1.8×10−5 at 25∘C Part A If a solution initially contains 0.265 molL−1 CH3COOH, what is the equilibrium concentration of H3O+ at 25∘C?

Explanation:

Hello.

In this case, for the given ionization chemical reaction of acetic, the equilibrium expression is:

Since aqueous species are considered only. Next, by introducing the reaction extent based on the ICE table, in which it equals the concentration of both H3O+ and CH3COO-, we can also write:

As the acid ionization constant is small in comparison to 0.265 M, we can make an approximation to compute as shown below:

It means that the concentration of H3O+ is:

Best regards.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l

answer: atomic mass was originally used to arrange elements on the periodic table, but is no longer used to organize the modern version.

explanation:

originally atomic mass was used to arrange elements on the periodic table from left to right in a row. each column then shows similar properties of elements of a group.

in modern periodic table, the atoms are arranged in increasing atomic number. as atomic number represents the number of protons in an atom which is unique for every atom.