Joebert had a rectangular cup and filled it with water. He measured the water's mass and volume. Then he got a density of 1.25g/ml. If the accepted density of water is 1 g/ml, what was the percent error of his measurement? someone can help me please?

Percent error = 25%

Explanation:

Given data:

Measured density of water = 1.25 g/mL

Accepted density value of water = 1 g/mL

Percent error = ?

Solution:

Formula:

Percent error = (measured value - accepted value / accepted value) × 100

Now we will put the values in formula:

Percent error = (1.25 g/mL - 1 g/mL /1 g/mL )× 100

Percent error = (0.25 g/mL /1 g/mL )× 100

Percent error = 0.25 × 100

Percent error = 25%

b. examine and describe cells

fe 55.85 g/mol and h2o 18.02 g/mol.