By pipet, 5.00 mL of a 0.823 M stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask and diluted to the calibration mark. Determine the molarity of the resulting solution.

0.0823 M

Explanation:

To solve this problem we can use the formula:

Where

C₁ = 0.823 M

V₁ = 5.00 mL

C₂ = ?

V₂ = 50.00 mL

So now it's just a matter of calculating C₂:

C₂ = 0.0823 M

The molarity of the resulting solution is 0.0823 M.

the answer is b & c i believe : )