Liquid hexane CH3CH24CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Supposed "54.3 g" of hexane is mixed with 82. g of oxygen. Calculate the minimum mass of hexane that could be left over by the chemical reaction. Round your answer to 2 significant digits.

31.1 g of C6H14.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation.

This is illustrated below:

Molar mass of C6H14 = (12×6) + (14×1)

= 72 + 14

= 86 g/mol

Mass of C6H14 from the balanced equation = 2 × 86 = 172 g

Molar mass of O2 = 16×2 = 32 g/mol

Mass of O2 from the balanced equation = 19 × 32 = 608 g

Summary:

From the balanced equation above,

172 g of C6H14 reacted with 608 g of O2.

Next, we shall determine the mass of C6H14 needed to react with 82 g of O2. This can be obtained as follow:

From the balanced equation above,

172 g of C6H14 reacted with 608 g of O2.

Therefore, Xg of C6H14 will react with 82 g of O2 i.e

Xg of C6H14 = (172 × 82)/608

Xg of C6H14 = 23.2 g

Therefore, 23.2 g of C6H14 is needed to react with 82 g of O2.

Finally, we shall determine the leftover mass of hexane, C6H14. This is illustrated below:

Mass of C6H14 given = 54.3 g

Mass of C6H14 that reacted = 23.2 g

Mass of C6H14 leftover =?

Mass of C6H14 leftover = (Mass of C6H14 given) – (Mass of C6H14 that reacted)

Mass of C6H14 leftover = 54.3 – 23.2

Mass of C6H14 leftover = 31.1 g

Therefore, 31.1 g of C6H14 were leftover.

answer: option (4) is the correct answer.

explanation:

areas which are at low altitudes and near the equator tend to receive direct sunlight from the sun. hence, heat energy or radiations from the sun make these areas warmer and they have warmest water.

whereas areas which are at high altitudes and away from the equator do no receive direct sunlight. hence, no direct contact from the sun makes these regions colder and thus, they have colder water.

thus, we can conclude that the statement areas at low latitudes near the equator have the warmest water because they receive the most direct sunlight best explains the relationship between an area's geography and the temperature of its surface water.

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