Explain how the rate of diffusion of a gas is related to its molar mass. Carbon dioxide gas (co2) defuse 3.2 times faster than an unknown gas. Determine the molar mass of the unknown gas. Show your work to explain your answer, giving specific values used to determine the answer.

the answer is b & c i believe : )

a polar bond is formed when electrons are shared unevenly between atoms

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally