Calculate the mass percent of oxygen in lead(II) nitrate. Round your answer to the nearest percentage.

29%

Explanation:

Given that the molar mass of lead II nitrate is 331 g/mol.

The formula of the compound is Pb(NO3)2.

There are six oxygen atoms present and the relative atomic mass of oxygen is 16.

Hence to find the percentage by mass of oxygen;

6(16)/331 × 100 = 29%

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