Given the isotopic symbol below- how many neutrons are present in this beryllium ion? Answer with just a number*
1 point
9
+2
Be
4.

5 neutrons.

Explanation:

The following data were obtained from the question:

Mass number = 9

Atomic number = 4

Charge = +2

Neutron number =.?

Next, we shall determine the number of protons in the beryllium ion. This can be obtained as follow:

The atomic number is simply the number protons present in the atom. Thus,

Proton = Atomic number

Atomic number = 4

Proton = Atomic number = 4

Finally, we shall determine the Neutron number as follow:

Mass number = 9

Proton number = 4

Neutron number =.?

Mass number = Proton + Neutron

9 = 4 + Neutron

Collect like terms

Neutron = 9 – 4

Neutron = 5

Thus, there are 5 neutrons b present in the beryllium ion.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.