Write a balanced equation for each of the acid-base reaction given below. a. Aqueous sulfuric acid with aqueous potassium hydroxide.

H2SO4 + 2KOH => K2SO4 + 2H2O

Explanation:

The acid-base reaction is a type of chemical reaction that involves the exchange of hydrogen ions.

The acid-base reaction between aqueous sulfuric acid ( H2SO4 ) and aqueous potassium hydroxide (KOH) is a neutralization reaction that results in potassium sulfate and water.

sulfuric acid + potassium hydroxide => potassium sulfate + water

So, the balanced equation for this reaction is as follows:

                  H2SO4 + 2KOH => K2SO4 + 2H2O

Hence, the correct answer is "H2SO4 + 2KOH => K2SO4 + 2H2O".

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm