Calculate the e. e. of a mixture containing 8.0 g of (-)-glyceraldehyde and 2.0 g of ( )-glyceraldehyde.

In stereochemistry, the enantiomeric excess (ee) of a substance is a measure of how pure it is. In this case, the impurity considered is the unwanted enantiomer: the mirror image of a chiral compound.

Which is 60% in this case

Explanation:

total mass of the mixture is = 10.09g

% of (-)-glyceraldehyde = 8.09/10.09 = 80%

by the same way, the % of ( )-glyceraldehyde is = 20%

the enantiomeric excess (e.e) are

e.e = %(-)-glyceraldehyde - %( )-glyceraldehyde

e.e = 80% - 20% = 60%

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i