If 30.8 grams of hydrobromic acid react to form 0.4 grams of hydrogen, how many grams of bromine must simultaneously be formed

30.4g of Br2

Explanation:

2HBr --> H2 + Br2

From the stochiometry of the reaction;

2 mol of HBr reacts to form 1 mol of Br2

Mass of HBr = Molar mass * Mol = 80.91 * 2 = 161.82g

Mass of Br2 =  Molar mass * Mol = 159.8 * 1 = 159.8g

161.82g of HBr forms 159.8g of Br2

30. 8g would the form x?

161.82 = 159.8

30.8 = x

x = 30.8 * 159.8 / 161.82 = 30.4g of Br2

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