Chemistry, 28.10.2020 17:40 syong

Lexi is balancing equations. She is finding one equation to be very difficult to balance. Which explains how to balance the equation ZnSO4 + Li2CO3 → ZnCO3 + Li2SO4? One reactant and one product needs the coefficient 2.
The products both need a 3 coefficient.
The reactants both need a 2 coefficient.
Atoms in the equation are already in balance.

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The statement that best explains how to balance the equation: ZnSO4 + Li2CO3 → ZnCO3 + Li2SO4 is: atoms in the equation are already in balance.

HOW TO BALANCE A CHEMICAL EQUATION:

A chemical equation is said to be balanced if the number of atoms of each element in the reactant side is equal to that on the product side.

In the equation given in this question as follows:

ZnSO4 + Li2CO3 → ZnCO3 + Li2SO4

There are:1 atom of Zn on both sides of the equation1 atom of sulfur on both sides of the equation7 atoms of oxygen on both sides of the equation2 atoms of lithium on both sides of the equation. Since the number of atoms of each element on both sides of the equation are the same, hence, the equation is said to be balanced. Therefore, the statement that best explains how to balance the equation: ZnSO4 + Li2CO3 → ZnCO3 + Li2SO4 is: atoms in the equation are already in balance.

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Answer from: Quest

60.0 - there are 3 significant numbers

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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Lexi is balancing equations. She is finding one equation to be very difficult to balance. Which expl...