An air bubble in a bar of ivory soap at room temperature (23 °C) has a volume of 0.80 mL. What volume does the air bubble have when it is
heated in a microwave to 88 °C? *

V2 = 0.98mL

Explanation:

Using Charles' law equation which I as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

T1 = initial temperature (K)

V2 = final volume (mL)

T2 = final temperature (K)

Based on the information provided in this question; V1 = 0.80 mL, V2 = ?, T1 = 23°C, T2 = 88°C

Temperature in °C must be converted to Kelvin

T1 (K) = 23°C + 273 = 296K

T2 (K) = 88°C + 273 = 361K

Hence, using V1/T1 = V2/T2

0.80/296 = V2/361

296 × V2 = 0.80 × 361

296V2 = 288.8

V2 = 288.8/296

V2 = 0.9756

V2 = 0.98mL

gas

explanation:

smoke is the matter of a gas